Question

What is the value of 3^2/3^4? pls help fast

Answer 1

Method #1:

`(3^2)/(3^4)=(3^2)/(3^(2+2))=(3^2)/(3^2\cdot3^2)=(1)/(3^2)=(1)/(9)`

Method #2:

`(3^2)/(3^4)=3^(2-4)=3^(-2)=(1)/(3^2)=(1)/(9)`

used:

`(a^m)/(a^n)=a^(n-m)\\\\a^(-n)=(1)/(a^n)`

Method #3:

`(3^2)/(3^4)=(\\ot3\cdot\\ot3)/(\\ot3\cdot\\ot3\cdot3\cdot3)=(1)/(9)`

Answer 2

Note that when you are dividing, and there is the same base, subtract

3^2/3^4 = 3^(2 - 4) = 3^(-2)

3^(-2) = 1/(3^2)

Simplify

1/(3^2) = 1/9

1/9 is your answer

hope this helps