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If P = 4x4 - 3x3 + x2 - 5x + 11 and Q = -3x4 + 6x3 - 8x2 + 4x - 3 what is 2P + Q?

1 Answer

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The given vaues of P and Q are


P = 4x^4 -3x^3+x^2 -5x +11


Q = -3x^4 + 6x^3-8x^2+4x-3

And we have to find the value of


2P +Q

For that, we have to multiply P by 2 and add the result to Q. That is


2P+ Q = 2(4x^4-3x^3+x^2-5x+11)-3x^4+6x^3-8x^2 +4x-3


= 8x^4 -6x^3 +2x^2 -10x +22-3x^4 +6x^3 -8x^2 +4x-3


= 5x^4-6x^2-6x+19

And that's the required result of 2P + Q .

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