Question

The force acting on a pendulum to bring it to its perpendicular resting point is called the restoring force. the restoring force f, in newtons, acting on a string pendulum is given by the formula f = mg sinθ where m is the mass in kilograms of the pendulum's bob, g ≈ 9.8 meters per second per second is the acceleration due to gravity, and θ is angle at which the pendulum is displaced from the perpendicular. what is the value of the restoring force when m = 0.6 kilogram and θ = 45°? if necessary, round the answer to the nearest tenth of a newton.

Answer 1

Restoring force
`=mg sin \Theta`

Given,
`m=0.6 kg` ,
`g= 9.0m/s^(2)` and
`\Theta = 45^(0)`

Substituting these value in above formula we get,

`F= 0.6 * 9.8 * sin  45^(0) N`

`F= 5.88 * sin(1)/(√(2) )`

`F= 4.15 N`
`\simeq  4.2 N`

Therefore, the value of restoring force is 4.2 N.