Question

How many helium atoms are there in a helium blimp containing 536 kg of helium? n = atoms?

Answer 1

Answer:-
`8.07*10^2^8atoms`

Solution:- It is a unit conversion where it asks to convert kg of He to atoms. We need to convert kg to grams, grams to moles and finally moles to atoms.

We know that, 1 kg = 1000 g

Molar mass of He is 4.0 grams per mole and 1 mole of an atom equals to Avogadro number of atoms.

The set up would be as given below:

`536kg((1000g)/(1kg))((1mole)/(4g))((6.02*10^2^3atoms)/(1mole))`

=
`8.07*10^2^8atoms`

So, there are
`8.07*10^2^8atoms` of He in it's 536 kg.