Answer:
a) 0.09
b) 0.36
c) No
Explanation:
Here We have given that P(Manager) = 0.15 , P(MBA) = 0.25 and P(MBA | Manger ) = 0.60
(a) Find the proportion of employees who are managers and have MBA degrees ?
That is we have to find P(Manager ∩ MBA) .
For any two events A and B, where P(B) ≠ 0, you have the conditional probability:
P( A | B ) = P( A ∩ B ) / P( B ) = P( B | A) * P(A) / P(B)
So P(Manager ∩ MBA) = P(MBA | Manger) * P(Manger)
= 0.60 * 0.15
= 0.09
(b) Find the proportion of MBAs who are managers.
that is we have to find P( Manger | MBA) .
P( Manger | MBA) = P( Manger ∩ MBA) / P(MBA)
= 0.09 / 0.25
= 0.36
(c) Are the events being a manager and having an MBA independent?
An event which remains unaffected by previous event or set of events is known as an independent event.
the probability of independent events A and B.
P(A and B) = P(A) * P(B)
P(Manager) = 0.15 , P(MBA) = 0.25 and P(Manager ∩ MBA) = 0.09
if events being a manager and having an MBA independent then P(Manager ∩ MBA) = P(Manager)* P(MBA)
= 0.15*0.25 = 0.0375
In this way the events being a manager and having an MBA are not independent. So answer is NO.