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30 cubic meters of argon gas are kept under constant pressure. the gas is heated from 10.0 degrees celsius to 293 degrees celsius. what is the new volume of the gas?

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Answer:

V₂ = 60 cm³

Step-by-step explanation:

According to Charle's Law, "Volume of given amount of gas is directly proportional to applied temperature at constant pressure". Mathematically,

V₁ / T₁ = V₂ / T₂ ---- (1)

Data Given:

V₁ = 30 cm³

T₁ = 10 °C = 10 + 273 = 283 K

V₂ = ?

T₂ = 293 °C = 293 + 273 = 566 K

Solution:

Solving equation 1 for V₂,

V₂ = V₁ × T₂ ÷ T₁

Putting values,

V₂ = (30 cm³ × 566 K) ÷ 283 K

V₂ = 60 cm³

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