Question

A new community sports complex is being built in Madison. The perimeter of the rectangular playing field is is 462 yards. The length of the field is 5 yards less than triple the width. What are the dimensions of the playing field?

Answer 1

we are given

The perimeter of the rectangular playing field is is 462 yards

Let's assume width=x

W=x

The length of the field is 5 yards less than triple the width

`L=3x-5`

we know that perimeter of rectangle is

`P=2L +2W`

now, we can plug values

`P=2(3x-5) +2x`

now, we can plug P=462

`462=2(3x-5) +2x`

now, we can solve for x

`8x-10=462`

`x=59`

so,

width =59

now, we can find length

`L=3*59-5`

`L=172`

so, dimensions are

length=172 yards and width=59 yards.........Answer