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What is the P0H of a solution of HN03 that has [0H-] = 9.50 x 10-9 M ?

What is the P0H of a solution of HN03 that has [0H-] = 9.50 x 10-9 M ?
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What is the P0H of a solution of HN03 that has [0H-] = 9.50 x 10-9 M ?

User JTG
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1 Answer

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pOH = -log(OH^(-)] = -log[9.50 × 10^(-9)] = 8.02

User Anesta
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