Question

How many atoms of oxygen are contained in 160 grams of N2O3?

Answer 1

above 80 grams 6 grams

Answer 2

Answer : The number of oxygen atoms are,
`37.94* 10^(23)`

Explanation : Given,

Mass of
`N_2O_3` = 160 g

Molar mass of
`N_2O_3` = 76.01 g/mole

First we have to calculate the moles of
`N_2O_3`

`\text{Moles of }N_2O_3=\frac{\text{Mass of }N_2O_3}{\text{Molar mass of }N_2O_3}=(160g)/(76.01g/mole)=2.1mole`

As we know that
`N_2O_3` contains 2 number of nitrogen atoms and 3 number of oxygen atoms.

Now we have to calculate the number of atoms of oxygen.

As, 1 mole of
`N_2O_3` contains
`3* 6.022* 10^(23)` number of oxygen atoms

As, 2.1 mole of
`N_2O_3` contains
`2.1* 3* 6.022* 10^(23)=37.94* 10^(23)` number of oxygen atoms

Therefore, the number of oxygen atoms are,
`37.94* 10^(23)`