Question

A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.0 gal tank (1us gal=3.78l)?

Answer 1

Density of gasoline is 0.737 g/mL and volume of tank is 13.0 gal.

Since, 1 US gal=3.78 L

Volume of tank in L will be:

`V=13.0 gal((3.78 L)/(1 gal))=49.14 L`

Also, 1 L=1000 mL

Thus,

`V=49.14 L((1000 mL)/(1 L))=49140 mL`

Mass of gasoline can be calculated as follows:

m=d×V

Here, d is density and V is volume thus,

`m=0.737 g/mL* 49140 mL=3.62* 10^(4)g`

Therefore, mass of gasoline will be
`3.62* 10^(4)g`.