Answer:
8.62 g of Hydrogen
Solution:
Molar mass of CH₄O (Methanol) is 32 g.mol⁻¹.
It means,
32 g of CH₄O contains = 4 g of Hydrogen
Then,
69 g of CH₄O will contain = X g of Hydrogen
Solving for X,
X = (69 g × 4 g) ÷ 32 g
X = 8.62 g of Hydrogen
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