Question

After an average acceleration of 3.39 m/s2 during 2.29 s, a car reaches a final velocity of 16.1 m/s. find the car's initial velocity.

Answer 1

Average acceleration is given by

`\bar a=(v-v_0)/(\Delta t)`

so we get

`3.39\,(\mathrm m)/(\mathrm s^2)=(16.1\,(\mathrm m)/(\mathrm s)-v_0)/(2.29\,\mathrm s)`

`\implies v_0=8.34\,(\mathrm m)/(\mathrm s)`

Answer 2

8.34 m/s

Step-by-step explanation:

Given data

• Initial velocity (u): ?

• Acceleration (a): 3.39 m/s²

• Time (t): 2.29 s

• Final velocity (v): 16.1 m/s

The car undergoes a uniformly accelerated motion. We can determine the initial velocity using the following kinematic expression.

v = u + a × t

16.1 m/s = u + 3.39 m/s² × 2.29 s

u = 8.34 m/s