Question

Moustapha jones reaches the bottom of a hill on his bike moving at a speed of 8.6 m/s when his chain breaks. he coasts up the hill until he comes to a stop after 3.5 s. find his acceleration while on the hill, and the distance he travelled up the hill.

Answer 1

1. Answer;

Acceleration is;

-2.46m/s²

Step-by-step explanation;

The initial velocity is 8.6 m/s, the final velocity = 0 m/s

The time is 3.5 seconds

Using the equation;

V =U + at

but V =0 , -U = at

a = -U/t = -8.6 /3.5

= -2.457 m/s²

= -2.46 m/s² (2 d.p)

2. Answer;

The distance is ;

=15.1 m

Solution;

a = -2.46 m/s², v=0 and U = 8.6 m/s

Using the equation;

V² = U² +2as (where s is the distance)

but v =0, thus, s =U²/2a

= -8.6²/ 2(-2.46)

= -73.96 /-4.92

= 15 .1 m (1 d.p)