Final answer:
The car starting at 110 km/h (30.6 m/s) decelerates to a stop over 4.5 seconds. The corresponding velocity versus time graph starts at 30.6 m/s, ends at 0 m/s, with a consistent negative slope (straight line) indicating constant deceleration.
Step-by-step explanation:
The driver of a car traveling at 110 km/h (approximately 30.6 m/s) applies the brakes, inducing a constant acceleration that brings the car to a complete stop in 4.5 seconds. To plot the velocity versus time graph for this scenario, we are considering a scenario of constant deceleration, which means the car slows down at a steady rate until it reaches a velocity of 0 m/s.
Since the car comes to a stop in 4.5 seconds, the slope of the velocity-time graph will be a straight line descending from the initial velocity to zero. The slope of this line represents the deceleration, and using the formula for acceleration a = Δv/Δt, we can calculate that the deceleration is 30.6 m/s / 4.5s = -6.8 m/s². This deceleration is negative because it is in the opposite direction of the car's initial velocity.
The most accurate velocity versus time graph for the car will start at 30.6 m/s on the y-axis and end at 0 m/s, with a constant negative slope representing uniform deceleration over the 4.5 seconds until the car comes to a stop.