We have the equation:
![(2)/(3)+(5)/(6)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/egt0kexeg0t6woq3h2ughlqrh2k02eto4a.png)
So we need to get both of the terms to have a common denominator. We can do this by multiplying both the numerator and denominator of the first term by 2 - this allows it to remain the same number, it just increases the value of the denominator:
![(2)/(2)*(2)/(3)=(4)/(6)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/qmxydzj777bq8l7a4i463jfm0h27plt0n7.png)
So then we can rewrite the expression:
![(4)/(6)+(5)/(6)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/z9jaoxgt9ft4ffxbk7fzfvqxtz8bfnmcbn.png)
And then we can add these fractions:
![(4)/(6)+(5)/(6)=(9)/(6)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/s6ga1xau7je3xkjqjj3mifw917uw7g4gq4.png)
Therefore, the answer would be D)
![(9)/(6)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/s5a0zou0kz6dzd8w3fidlsrq0ctdiplxw8.png)
**Note: These answer could further be simplified to
by dividing both the numerator and denominator by 3, however the answer choice is not there - for future reference though, you could further reduce.