Upper Tolerance
Remark
The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.
Solution
Upper Limit
![(11)/(16) + (1)/(64)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/vaaeqx3pg4zpf90lek3zb5472pw13e2qs9.png)
Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4
![(11*4)/(16*4) + (1)/(64)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/dcrmb371wcfsgnheq1d4108wl2bpkaglpq.png)
Which results in
![(44)/(64) + (1)/(64)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/evdrhlyw2bk7v0fqh1bmni17999ioas8ae.png)
With a final result for the fractions of 45/64
So the upper tolerance = 3 45/64
Lower Tolerance
Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.
![(11)/(16) - (1)/(64)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/z1vnibh8pdh1r2xx34bayiriodjdx5b4rh.png)
Your answer should be 3 and 43/64