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The velocity of a ball as it is thrown up is 20 meters/second. It attains zero velocity after 3.5 seconds. What is the average acceleration of the ball during its upward flight? A. 5.7 meters/second B. 0.57 meters/second C. -0.57 meters/second2 D. -5.7 meters/second2 E. 5.5 meters/second2

User R Yoda
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2 Answers

6 votes

Average acceleration = (change in speed) / (time for the change)

If a ball is thrown upwards at a speed of 20 m/s, and reaches the top of its arc with zero speed after 3.5 seconds, then its average acceleration is

(0 - 20 m/s) / (3.5 s) =

(-20 m/s) / (3.5 s) =

-5.71 m/s² .

Note: This could not be happening on Earth, and there's no planet or other body in our solar system with a gravitational acceleration anywhere near that number.

User Phani Bob
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3 votes

The average acceleration is


\bar a=(\Delta v)/(\Delta t)=(0\,(\mathrm m)/(\mathrm s)-20\,(\mathrm m)/(\mathrm s))/(3.5\,\mathrm s-0\,\mathrm s)=-5.7\,(\mathrm m)/(\mathrm s^2)

so the answer is D.

User Jayden Meyer
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