Question

Indicate a general rule for the nth term of the sequence a1 = 2 and r = √3.

an = (√3)(2)^n+1
an = (√3)(2)^n-1
an = (2)(√3)^n-1
an = (2)(√3)^n+1

Answer 1

the correct answer is an = (2)(√3)^n-1

Answer 2

It is given in the question that,

`a_(1) = 2, r = \sqrt 3`

Since we have the value of r given, so we have to use the formula to find the nth term of the geometric progression, which is

`a_(n) = a(r)^(n-1)`

Substituting the values of a and r, we will get

`a_(n) = 2( \sqrt 3)^(n-1)`

So the correct option is the third option .