Answer: 1.45 moles of
![Na_2O](https://img.qammunity.org/2019/formulas/chemistry/high-school/7lyazdgrrhnyg7xtkj3628zgtkar0g9826.png)
Step-by-step explanation:
![4Na+O_2\rightarrow 2Na_2O](https://img.qammunity.org/2019/formulas/chemistry/high-school/lzpxxhw80nvpufnjocbwfl9bqhnnvlhcgg.png)
According to the stoichiometry:
Given : Na react completely, thus sodium is a limiting reagent as it limits the formation of product. Oxygen will be excess reagent as it does not react completely.
4 moles of sodium produce 2 moles of
![Na_2O](https://img.qammunity.org/2019/formulas/chemistry/high-school/7lyazdgrrhnyg7xtkj3628zgtkar0g9826.png)
Thus 2.90 moles of sodium produce =
moles of
![Na_2O](https://img.qammunity.org/2019/formulas/chemistry/high-school/7lyazdgrrhnyg7xtkj3628zgtkar0g9826.png)
Thus 1.45 moles of
will be produced.