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An airplane has a takeoff speed of 62 m/s. assuming a constant acceleration of 1.7 m/s2, what is the minimum length of runway it needs for takeoff?

User Ben Reed
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Data:

u=0 m/s is the initial velocity of the plane

v=62 m/s is the final velocity of the plane (at which the plane takes off)

a=1.7 m/s^2 is the acceleration of the plane

To find the minimum distance S the plane needs to take off, we can use the following equation:


2aS=v^2 -u^2

Re-arranging it and substituting the numbers, we find


S=(v^2-u^2)/(2a)=((62 m/s)^2-0)/(2(1.7 m/s^2))=1131 m

User Reshat Belyalov
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