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You can respect an odd integer with the expression 2n+1, where no is any integer. Write and solve an equation to find three consecutive odd integers that have the sum of 63.

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First Odd Integer: 2k + 1

Second Odd Integer: 2k + 3

Third Odd Integer: 2k + 5

(2k + 1) + (2k + 3) + (2k + 5) = 63

6k + 9 = 63

6k = 54

k = 9

First Odd Integer: 2k + 1 = 2(9) + 1 = 18 + 1 = 19

Second Odd Integer: 2k + 3 = 2(9) + 3 = 18 + 3 = 21

Third Odd Integer: 2k + 5 = 2(9) + 5 = 18 + 5 = 23

Answer: 19, 21, 23

User FabLouis
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