Question

The daily production of carbon dioxide from an 780.0 mw coal-fired power plant is estimated to be 3.3480 x 104 tons (not metric).a proposal has been made to capture and sequester the co2 at approximately 300 k and 140 atm. at these conditions, the specific volume of co2 is estimated to be 0.0120 m3/kg.what volume of co2 would be collected in a 4.00 year period?

Answer 1

The production of
`CO_(2)` is
`3.3480* 10^(4) tons/day`. Converting mass into kg,

1 ton=907.185 kg, thus,

`3.3480* 10^(4) tons=3.037* 10^(7) kg`

Thus, production of
`CO_(2)` will be
`3.037* 10^(7) kg/ day`.

The specific volume of
`CO_(2)` is
`0.0120 m^(3)/kg`.

Volume of
`CO_(2)` produced per day can be calculated as:

`V=Specific volume* mass`

Putting the values,

`V=0.0120 m^(3)/kg* 3.037* 10^(7) kg=364440 m^(3)/day`

Thus, volume of
`CO_(2)` produced per year will be:

`V=(365 days)/(1 year)(364440 m^(3)/day)=1.33* 10^(8)m^(3)/year`

Thus, in 4 year volume of
`CO_(2)` produced will be:

`V=1.33* 10^(8)m^(3)/year* 4 years=5.32* 10^(8)m^(3)`