we know that
1 ft is equal to 12 in
1 cubic yard is equal to 27 cubic feet
Step 1
Find the area of the circular border of uniform width around the pool
Let
x---------> the uniform width around the pool
we know that
The diameter of the circular pool measures 10 feet
so
the radius r=5 ft
the area of the circular border is equal to
![A=\pi *(5+x)^(2)- \pi *5^(2) \\A= \pi *[(x+5) ^(2)-5^(2) ] \\ A= \pi * [x^(2) +10x]](https://img.qammunity.org/2019/formulas/mathematics/high-school/fyfr2jils6dai5jx84n6vclsmvzpgl6ee9.png)
step 2
volume of the concrete to be used to create a circular border is equal to
V=1 yd^{3}-------> convert to ft^{3}
V=27 ft^{3} -------> equation 1
the depth is equal to 4 in-------> convert to ft
depth=4/12=(1/3) ft
volume of the concrete to be used to create a circular border is also equal to
V=Area of the circular border*Depth
-------> equation 2
equate equation 1 and equation 2
![27=\pi * [x^(2) +10x]*(1/3) \\ x^(2) +10x- (81)/(\pi )=0](https://img.qammunity.org/2019/formulas/mathematics/high-school/eyaql53mvvi1el9ste83obb1gmsfqf4xig.png)
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is the point
x=2.126 ft
therefore
the answer is
The uniform width around the circular pool border is 2.126 ft