The answer in English
A goat has been tied with a rope 15 m long, in one of the corners of a rectangular meadow 20x30 m. Calculate the surface of the meadow on which the goat can graze.
we know that
the surface of the meadow on which the goat can graze is a quarter of a circle
the area of the surface of the meadow is equal to
![A= (1)/(4) * \pi *r^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/5acim6jk14comtaob4eaot4ed4zbagkvjh.png)
where
r=15 m
substitute
![A= (1)/(4) * \pi *15^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/w1p5n6hoorsn5h2uk1ae5tsvwr13mkunj9.png)
![A= 176.71 \ m^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/8k6pqv4zvgc99pj37awxabmutu5d79luw2.png)
therefore
the answer is
the area of the surface of the meadow on which the goat can graze is
![176.71 \ m^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/20ceq44s09t77oshup43jmcji0say4biq9.png)
The answer in Spanish
Sabemos que
la superficie del prado en el que se puede pastar la cabra es igual al area de un cuarto de circulo
El area de la superficie del prado es igual a
![A= (1)/(4) * \pi *r^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/5acim6jk14comtaob4eaot4ed4zbagkvjh.png)
donde
r=15 m
sustituya
![A= (1)/(4) * \pi *15^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/w1p5n6hoorsn5h2uk1ae5tsvwr13mkunj9.png)
![A= 176.71 \ m^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/8k6pqv4zvgc99pj37awxabmutu5d79luw2.png)
por lo tanto
La respuesta es
El area de la superficie del prado en el que se puede pastar la cabra es igual
![176.71 \ m^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/20ceq44s09t77oshup43jmcji0say4biq9.png)