Question

How many grams of glucose would be present in one liter of a 1 m solution of glucose?

Answer 1

Mass = 180 g

Solution:

Step 1: Calculate Moles using following Formula,

Molarity = Moles ÷ Volume

Solving for Moles,

Mole = Molarity × Volume

Putting values,

Mole = 1 mol.L⁻¹ × 1 L

Mole = 1 moles

Step 2: Calculate mass using following formula,

Moles = Mass ÷ M.Mass

Solving for Mass,

Mass = Moles × M.Mass

Putting Values,

Mass = 1 mol × 180 g.mol⁻¹

Mass = 180 g