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HELPWW! The equation of a circle is (x + 6)2 + (y - 4)2 = 16. The point (-6, 8) is on the circle. What is the equation of the line that is tangent to the circle at (-6, 8)? A) y = 8 B) x = 8 C) x = -2
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HELPWW!

The equation of a circle is (x + 6)2 + (y - 4)2 = 16. The point (-6, 8) is on the circle.

What is the equation of the line that is tangent to the circle at (-6, 8)?

A) y = 8

B) x = 8

C) x = -2

D) y = 0

User Kuiken
by
5.7k points

1 Answer

5 votes
The answer is A. The line would run through the point (-6,8) and run parallel to the x -axis, tangent to the circle.
HELPWW! The equation of a circle is (x + 6)2 + (y - 4)2 = 16. The point (-6, 8) is-example-1
User Rick Sladkey
by
6.6k points
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