we are given that
8 more than a number is greater than or equal to 0
Let's assume that number as 'x'
8 more than a number is
![x+8](https://img.qammunity.org/2019/formulas/mathematics/high-school/ee9ilwqp81rpstorfxlinc7iip1pjb5abd.png)
now, it is greater than or equal to 0
so, we can write as
![x+8\geq 0](https://img.qammunity.org/2019/formulas/mathematics/college/pz8mga38cqclksplhxpe7mo6jjxd3hpvlj.png)
now, we can solve for x
Subtract both sides 8
![x+8-8\geq 0-8](https://img.qammunity.org/2019/formulas/mathematics/college/o27tihye0jbzddyqpzgdl2xy426ku8qzac.png)
...............Answer