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How much energy is required to bring a 122g block of ice at -45 to steam at 190 degrees?
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25 votes
25 votes
How much energy is required to bring a 122g block of ice at -45 to steam at 190
degrees?

User Ali Tamoor
by
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1 Answer

8 votes
8 votes

Answer:

Step-by-step explanation:


The amount of the water, m = 200 L = 2.0×105 gThe initial temperature of the water, T1 = 18∘CThe final temperature of the water, T2 = 60∘CThe specific heat of the water, C = 4.184 J/g−∘CThe energy required by the water can be given asE = mC(T2−T1)→E = 2.0×105 g×4.184 J/g−∘C×(60−18)∘C→E = 2.0×105×4.184×42 J∴E = 3.51×107 JHence the energy required for this process is 3.51×107 J.

User Ruzanna
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