Answer:- 40 drops and the percentage of acid in acid solution is 0.166%.
Solution:- Acid is added drops wise to 1.2 L of water to make acid solution. The final volume of the acid solution is 1.202 L. From here we could calculate the volume of the acid added to water by subtracting water volume from final acid solution volume as:
volume of acid added = 1.202 L - 1.2 L = 0.002 L
It's given that the volume of each drop is 0.05 mL. let's convert the volume of acid added from L to mL.
![0.002L((1000mL)/(1L))](https://img.qammunity.org/2019/formulas/chemistry/high-school/k902tlwatyhjc8zx2zjft5iqy7cr6403mf.png)
= 2mL
Now let's calculate the number of drops of acid added to water as:
![2mL((1drop)/(0.05mL))](https://img.qammunity.org/2019/formulas/chemistry/high-school/7mu2i3yascddc3nfkk4szwbihi7owiziz0.png)
= 40 drops
0.002 L of acid are present in 1.202 L of solution. It asks to calculate about what percent of acid solution is acid means how many L of acid are present in 100 L of acid solution. It's done as:
percentage of acid in acid solution =
![((0.002)/(1.202))100](https://img.qammunity.org/2019/formulas/chemistry/high-school/4asfxx03cy6iq9zqdj1iqy671u3vtjhw4z.png)
= 0.166%
So, 40 drops of acid are required and there is 0.166% of acid in acid solution.