Question

A gas sample occupies 3.25 liters at 297.5K and 2.4 atm. Determine the temperature at which the gas will occupy 4.25 L at 1.50 atm.

what is the answer of this

Answer 1

By combining the three laws: Boyle's, Charles', and Gay-Lussac's Laws we get the combined gas law that is:

`(P_1V_1)/(T_1) = (P_2V_2)/(T_2)`

where
`P` is pressure,
`V` is volume, and
`T` is temperature.

`P_1 = 2.4 atm, V_1 = 3.25 L, T_1 = 297.5 K`

`P_2 = 1.50 atm, V_2 = 4.25 L`

Substituting the values,

`(2.4 atm* 3.25 L)/(297.5 K) = (1.5 atm * 4.25 L)/(T_2)`

`{T_2} = (1.5 atm * 4.25 L* 297.5 K)/(2.4 atm* 3.25 L)`

`{T_2} = 243.149 K`

Thus, the temperature is
`{T_2} = 243.149 K`.