How would I solve this? g(x)=(5x)/(x^(2)-36) It has to be in interval notation

asked May 8, 2019 132k views

0 votes

How would I solve this?

g(x)=
(5x)/(x^(2)-36)

It has to be in interval notation

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3 votes

$x^2-36\\ot =0\\x^2\\ot =36\\x\\ot =-6 \wedge x\\ot =6\\\\D_f:x\in\mathbb{R}\setminus\{-6,6\}$

Interval notation:

$D_f:x\in(-\infty-6)\cup(6,\infty)$

E Ciotti answered May 12, 2019

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