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11. 3n^2-n/n^2-1 divided by n^2/n+1

User Jobsamuel
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(3n^2-n)/(n^2-1)/(n^2)/(n+1)=(n(3n-1))/(n^2-1^2)\cdot(n+1)/(n^2)=(3n-1)/((n-1)(n+1))\cdot(n+1)/(n)\\\\=(3n-1)/(n-1)\cdot(1)/(n)=(3n-1)/(n^2-n)


Used:\\\\a^2-b^2=(a-b)(a+b)

User Essan Parto
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