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4 votes
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Carmelo is selling his hockey and baseball card collection. Hockey cards, x, sell for $0.03 and baseball cards, y, sell for $0.05. The number of hockey cards Carmelo sells is at least six times the number of baseball cards he sells. He has at most 525 cards to sell.

What is the maximum revenue he can make?


A. $15.75

B. $17.25

C. $26.25

D. $28.50

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! Carmelo is selling his hockey and-example-1

2 Answers

1 vote
B
0/05×75=3/75
0/03×450=13/5
13/5+3/75=17/25
User Keval Domadia
by
5.3k points
4 votes

Answer:

The maximum revenue Carmelo can make is $17.25.

Explanation:

Hockey cards, x, sell for $0.03 and baseball cards, y, sell for $0.05.

The number of hockey cards Carmelo sells is at least six times the number of baseball cards he sells. There are at most 525 cards to sell.

Set of equations are :


x= 6y .....(1)


x+y= 525 ......(2)

Substituting x=6y in the second equation.

=>
6y+y = 525

=>
7y=525

y = 75

And we know x = 6y; so
x=6(75)

x = 450

Total revenue =
(450*0.03)+ (75*0.05)

=
13.50+3.75

= $17.25

Hence, the maximum revenue Carmelo can make is $17.25.

User Vitaliy Kurokhtin
by
5.8k points
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