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$7000 is compounded semiannually at a rate of 11% for 21years Find the total amount and round to the nearest cent

User Stirfries
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\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\ \\ \text{we know that the amount after t year when compounded is given by}\\ \\ A=P\left ( 1+(r)/(n) \right )^(nt)\\ \\ \text{here P is the principal amoount, so }P=7000,\\ \\ \text{r is the interest rate, }r=11\%=0.11\\ \\ \text{n is the number of times in a year, here semiannulay, so }n=2,\\ \\ \text{and t is the time, so }t=21\\ \\ \text{so the amount after 21 years is}


A=7000\left ( 1+(0.11)/(2) \right )^(2(21))\\ \\ \Rightarrow A=7000\left ( 1+0.055 \right )^(42)\\ \\ \Rightarrow A=7000\left ( 1.055 \right )^(42)\\ \\ \Rightarrow A\approx 66328.68

So the amount after 21 years is: $66328.68

User Yanna
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