Answer: 1.2 s
It is given that a ball is thrown vertically upwards with initial velocity, u= 12 m/s.
At the maximum height, instantaneous velocity would be, v= 0 m/s
the ball would decelerate due to gravity,
![g=-9.8m/s^(2)](https://img.qammunity.org/2019/formulas/physics/college/h5gsm8dbou2i5r696ehy80d4l9g7fo35io.png)
using equation of motion,
![v-u=gt\\ \Rightarrow t=(v-u)/(g) \\ \Rightarrow t= \frac {0-12 m/s}{9.8 m/s^(2)}=1.2s](https://img.qammunity.org/2019/formulas/physics/college/2n9hwb9fdrfti63673hfg1mrcg5cjcypxx.png)
Hence, the time taken by ball to reach its maximum height is 1.2 s when thrown vertically upward with initial velocity of 12 m/s.