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The density of lead is 11.3 g/ml. the water level in a graduated cylinder initially at 215 ml rises to 285 ml after a piece of lead is submerged. what is the mass, in grams, of the lead?

2 Answers

4 votes

Final answer:

To find the mass of the submerged lead, calculate the volume of water displaced and then use the density of lead to find the mass. The mass of the lead is 791 grams after using the given density (11.3 g/mL) and the volume change in the graduated cylinder (70 mL).

Step-by-step explanation:

To find the mass of the lead, we can use the formula:

density = mass/volume

We know the density of lead is 11.3 g/mL and the change in volume is (285 mL - 215 mL) = 70 mL. Rearranging the formula, we can solve for mass:

mass = density * volume

mass = 11.3 g/mL * 70 mL = 791 g

The mass of the lead is 791 grams

User Jet Basrawi
by
5.6k points
3 votes

Answer: 791 g

Given:

Initial volume,
V_1=215mL (when only water is present.

when lead is added

Final volume,
V_2=285mL

Denisty of lead = 11.3 g/mL

Formula Used:

Mass= Density
* volume

Volume of lead,
V= V_2-V_1\\ \Rightarrow V=285-215 =70mL

Mass of lead =11.3g/mL
*70mL=791g



User Jacob Bridges
by
5.2k points