Question

A 1.5m wire carries a 3 A current when a potential difference of 84 V is applied. What is the resistance of the wire?

Answer 1

The current flowing through the wire =
`3 A`

The applied potential difference =
`84 V`

Using Ohm's Law, that is the the voltage across the two points is directly proportional to the current flowing through the two points of the conductor. The formula is:

`I \alpha V`

`V = IR`

where V is the voltage difference, I is the current and R is the resistance of the conductor.

Substituting the values in the formula:

`84 = 3* R`

`R = (84)/(3) = 28 \Omega`

So, the resistance of the wire is
`28 \Omega`.

Answer 2

Resistance can be calculated using equation:

`V=I* R`

`R=(V)/(I)`

Here, V denotes voltage

I denotes current

R denotes resistance

Here V is given as 84 V

I is given as 3 A

So by putting all the values in the equation, we will get:

`84=3* R`

`R=(84)/(3)`

R=28 ohm

So, resistance here will be 28 ohm .