y = x² + 3x - 7
y - 5x + 8 → y = 5x - 8
5x - 8 = x² + 3x - 7 substituted "y" in first equation with "5x - 8"
0 = x² - 2x + 1 subtracted 5x and added 8 to both sides
0 = (x -1)(x - 1) factored x² - 2x + 1
x = 1 solved for "x"
Now plug that "x = 1" into "y = 5x - 8" → y = 5(1) - 8 → y = 5 - 8 → y = -3
Solution is (1, -3) so there is only one solution.
Answer: C