Question 20 please thank hou

asked Apr 8, 2019 207k views

5 votes

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4 votes

$(9mn-6m)/(25-m^2)/(12mn)/(5+m)=(3m(3n-2))/(5^2-m^2)\cdot(5+m)/(3m\cdot4n)\\\\=(3n-2)/((5-m)(5+m))\cdot(5+m)/(4n)=(3n-2)/(4n(5-m))\to\boxed{C.}$

Hau answered Apr 12, 2019

by Hau

7.8k points

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