The width of the border will be 0.5 ft
Step-by-step explanation
The length of the rectangular quilt is 5 ft and width is 4 ft.
So, the area of the rectangular quilt
![= (length* width)= (5*4)ft^2 = 20 ft^2](https://img.qammunity.org/2019/formulas/mathematics/high-school/ir3puflf0jax4vkq5jub5gsgol2r8gx853.png)
Lets assume, the width of the quilt's border is
ft.
So, the total length of the quilt including the border will be (2x+5) ft and width will be (2x+4) ft
So, the area of the quilt including the border = (2x+5)(2x+4) ft²
As the area of the border is 10 ft² , so the equation will be ...
![(2x+5)(2x+4) - 20 = 10 \\ \\ 4x^2+18x+20 -20 = 10\\ \\ 4x^2 +18x=10\\ \\ 2x^2 +9x= 5\\ \\ 2x^2 +9x-5=0 \\ \\ 2x^2 +10x-x-5=0\\ \\ 2x(x+5)-1(x+5)=0\\ \\ (x+5)(2x-1)=0](https://img.qammunity.org/2019/formulas/mathematics/high-school/ojbe8hp56ohxaj7gyo24q60l0mn5y7dsto.png)
Now applying zero-product property, we will get...
![x+5=0 \\ x=-5](https://img.qammunity.org/2019/formulas/mathematics/high-school/vk7liw168pw1fbyw6howb4jznekr6gpr61.png)
and
![2x-1=0\\ 2x= 1\\ \\ x= (1)/(2) =0.5](https://img.qammunity.org/2019/formulas/mathematics/high-school/22amo23kor2vev7646izne1vqy63u8ho3n.png)
As the width of the border can't be negative, so we will only take x = 0.5 ft
So, the width of the border will be 0.5 ft