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math carver jogs 4 times a week. last week his distance were 4 1/3, 3 1/2, 3 5/6 abd 4 1/6, all measured in miles. what was the carvers average distance for the 4 days? express your answer as a mixed number

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Given, Math Carver jogs 4 times a week.

Last week the distance which he covered are
4(1)/(3) miles,
3(1)/(2) miles,
3(5)/(6) miles,
4(1)/(6) miles.

We have to find the average distance for 4 days.

We have to convert the mixed fractions to improper fraction first.


4(1)/(3) =((4)(3)+1)/(3) =(12+1)/(3) =(13)/(3)


3(1)/(2)=((3)(2)+1)/(2) =(6+1)/(2) =(7)/(2)


3(5)/(6) =((3)(6)+5)/(6)=(18+5)/(6)=(23)/(6)


4(1)/(6) =((4)(6)+1)/(6)=(24+1)/(6) =(25)/(6)

Now to find average we have to add them and divide it by 4.

By adding the distances we will get,


(13)/(3) +(7)/(2) + (23)/(6) +(25)/(6)

To add them first we have to make common denominator. Here the denominators are 3, 2, 6, 6. So we can check the common denominator is 6 here.

To make the denominator of
(13)/(3) as 6 we will multiply the numerator and denominator both by 2. We will get,


((13)(2))/((3)(2)) =(26)/(6)

Similarly,
(7)/(2) =((7)(3))/((2)(3)) =(21)/(6)


(26)/(6) +(21)/(6) +(23)/(6)+(25)/(6)

As the denominators are same we will add the numerators. We will get,


((26+21+23+25))/(6)

=
(95)/(6)

Now the average distance

=
((95)/(6))/(4)

=
((95)/(6))((1)/(4))

=
((95)(1))/((6)(4))

=
(95)/(24)

We have got the average distance in improper fraction. We will convert it to mixed fraction.


(95)/(24) =((3)(24)+23)/(24) = 3(23)/(24)

So we have got the required answer.

The average distance is
3(23)/(24) miles.

User Sneftel
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