Question

How do you solve this?

Answer 1

Use BEDMAS:

B - Brackets

E - Exponents

D - Division

M - Multiplication

A - Addition

S - Subtraction

`6-(18-3^2)/(4+(2-3))=6-(18-9)/(4+(-1))=6-(9)/(3)=6-3=3`

Answer 2

Here is the equation:

`6-(18-3^(2))/(4+(2-3))`

Use PEMDAS

`Parentheses \\ Exponents \\ Multiplication \\ Division \\ Addition \\ Subtraction`

Parentheses is first:

`2-3 = -1`

Next is exponents:

`3^(2) = 3 * 3 = 9`

Your new equation is:

`6-(18-9)/(4+(-1))`

Simplify the fraction:

`(18-9)/(4+(-1)) = (9)/(3) = 3`

Your new equation is:

`6-3`

Subtract:

`6-3=3`

Your answer is:

`6-(18-3^(2))/(4+(2-3)) = \bf 3`