g(x) = \frac{x}{ \sqrt{9 - x {}^(2) } } find g(4/3)

asked Feb 28, 2019 63.0k views

3 votes

$g(x) = \frac{x}{ \sqrt{9 - x {}^(2) } }$
find g(4/3)

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3 votes

Hi,

Let's solve this.

x = (4)/(3) = 1.33

$g( (4)/(3) ) = \frac{4 / 3}{ \sqrt{9 - {4 / 3}^(2) } }$

$g( (4)/(3) ) = - 1.11 * {10}^( - 14)$

$g = - 1.11 * {10}^( - 14) + 1.33$

g = 1.32

Hope this helps.
r3t40

Mirko Lugano answered Mar 7, 2019

7.5k points

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