G(x) = \frac{x}{ \sqrt{9 - x {}^(2) } } find g(4/3)

Question

`g(x) = \frac{x}{ \sqrt{9 - x {}^(2) } }`
find g(4/3)

Answer 1

Hi,

Let's solve this.


`x = (4)/(3) = 1.33`

`g( (4)/(3) ) = \frac{4 / 3}{ \sqrt{9 - {4 / 3}^(2) } }`

`g( (4)/(3) ) = - 1.11 * {10}^( - 14)`

`g = - 1.11 * {10}^( - 14) + 1.33`

`g = 1.32`

Hope this helps.
r3t40