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What is the absolute value of (3+4i) (3-4i)

User Manveti
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1 Answer

6 votes

First simplify. Use (a + b)(a - b) = a² - b²:


(3+4i)(3-4i)=3^2-(4i)^2=9-4^2i^2=9-16(-1)=9+16=25

Absolute value:


|(3+4i)(3-4i)|=|25|=25

User Shaimagz
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