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) a rectangle has perimeter 40 feet and an area of 96 square feet. find the dimensions of the rectangle assuming the width is smaller than the length.

User Bivas
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1 Answer

3 votes

w=P

4+1

4P2﹣16A=40

4+1

4·402﹣16·96=12ft

w=P

4﹣1

4P2﹣16A=40

4﹣1

4·402﹣16·96=8ft

User Panjo
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