No. To compute the median, you arrange the whole dataset in increasing order, and pick the element in the middle. So, you have
observations so far, you write the dataset as
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And the median is the element in the middle, i.e

Now, assume you add the last observation,
. This is much larger than the rest of the dataset, so if we arrange the dataset in increasing order, it will be the last:

But the median is always the element in the middle, so it is again either
or
