Question

Please please help if you can!

Answer 1

`h(x) = x^(2) -5`

Since x is equal to -7, substitute all the x's with -7.

`h(-7) = -7^(2) -5`

`Parentheses \\ Exponents \\ Multiplication \\ Division \\ Addition \\ Subtraction`

Exponents is first:

`-7^(2) = -7 * -7 = 49`

Your new equation is:

`49-5`

Subtract:

`49 - 5 = 44`

Your answer is:

`h(-7) = \bf 44`