Question

Assuming ideal behavior, what is the vapor pressure of a solution of 16.0 mol of carbon tetrachloride and 4.00 mol of dioxane (c4h8o2)at 23.0 oc? vapor pressure at 23.0 oc carbon tetrachloride 100. mm hg dioxane 38.0 mm hg

Answer 1

Mole fraction of both the gases:

Mole fraction of
`CCl_(4)`=
`(Moles of CCl_(4))/(total moles)`

Mole fraction of
`CCl_(4)`=
`(16)/(16+4)=(16)/(20) = 0.8`

Mole fraction of
`CCl_(4)`=
`(Moles of CCl_(4))/(total moles)`

Mole fraction of dioxane =
`(moles of dioxane)/(total moles)`

Mole fraction of dioxane =
`(4)/(16+4)=(4)/(20) = 0.2`

Total pressure of the solution is given by:

mol fraction of
`CCl_(4)`
`*` partial pressure of
`CCl_(4)` + mol fraction of dioxane
`*` partial pressure of dioxane

Equating the values in the above equation:

Total pressure of the solution is:

= 0.8
`*` 100 mmHg + 0.2
`*` 38 mmHg

= 87.6 mmHg