Question

When 1 molecule of calcium phosphate is added to water, what and how many ions are formed? remember that ions are charged and so you must indicate the correct charge on each ion to receive credit for this question?

Answer 1

Calcium phosphate (Ca3(PO4)2) dissociates into three calcium ions (Ca2+) with a 2+ charge and two phosphate ions (PO4)3- with a 3- charge in water, maintaining electrical neutrality.

Step-by-step explanation:

When calcium phosphate, with the empirical formula Ca3(PO4)2, is added to water, it dissolves to some extent into ions. According to the solubility product equilibrium:

Ca3(PO4)2(s) ⇌ 3Ca2+ + 2PO43-

For every molecule of calcium phosphate that dissolves, three calcium ions (Ca2+) are formed, each with a 2+ charge, and two phosphate ions (PO43-) are formed, each with a 3- charge. This is because the compound must remain electrically neutral, thus the ratio of calcium to phosphate must balance the charges. The formula mass of calcium phosphate is found by adding the atomic masses of three calcium atoms, two phosphorus atoms, and eight oxygen atoms.

Answer 2

Asnwer :When 1 molecule of calcium phosphate is added to water, total 5 ions are formed 3 ions of Calcium(
`Ca^(2+)`) and 2 ions of Phosphate(
`PO_(4)^(3-)`)

Explanation : When Calcium phosphate is added to water it gets dissociated into ions. Calcium phosphate (
`Ca_(3)(PO_(4))_(2)`) dissociates into 3 ions of Calcium
`Ca^(2+)` and 2 ions of Phosphate
`PO_(4)^(3-)`.

Dissociation equation of calcium phosphate is :

`1 Ca_(3)(PO_(4))_(2) \leftrightarrow 3 Ca^(2+) + 2PO_(4)^(3-)`

From the dissociation equation we can conclude that total 5 ions are formed when 1 molecule of calcium phosphate is added to water.