Question

What is the solution to the system of equations?

Answer 1

`\left \{ {{4x~-~3y~ = ~26} \atop {3x~+~2y~=~11}} \right.`

Solve for x in the first equation.

1. Add 3y to both sides.
2. 4x = 26 + 3y
3. Divide both sides by 4.
4. x = 26/4 + 3/4y

Plug x into the second equation.

1. 3(26/4 + 3/4y) + 2y = 11
2. Distribute 3 inside the parentheses.
3. 78/4 + 9/4y + 2y = 11
4. Combine like terms.
5. 78/4 + 17/4y = 11
6. Subtract 78/4 from both sides.
7. 17/4y = -8.5
8. Divide both sides by 17/4.
9. y = -2

Plug -2 for y into the first equation.

1. 4x - 3(-2) = 26
2. Multiply -3 * (-2).
3. 4x + 6 = 26
4. Subtract 6 from both sides.
5. 4x = 20
6. Divide both sides by 4.
7. x = 5

x = 5, y = -2 is your solution.